Day trip from London to Waterloo
Waterloo lies 79 km (49 mi) north-east of London, in the same time zone. What the numbers say about getting there.
At 79 km (49 mi) apart, Waterloo is a realistic day trip from London: about 1 h 17 min each way by road.
| London | Waterloo | |
|---|---|---|
| Country | Canada | Canada |
| Population | 422,324 | 104,986 |
| Elevation | 252 m (827 ft) | 325 m (1,066 ft) |
| Time now | UTC-4 (America/Toronto) | UTC-4 (America/Toronto) |
What to see in Waterloo
| Sight | Visitors a year | Year |
|---|---|---|
| Waterloo Public Library | 11,687 | 2016 |
The busiest is Waterloo Public Library at 11,687 visitors in 2016. Figures are the latest each site has published, so they are not all for the same year.
Where to book tours and tickets in Waterloo
We take no bookings for these providers and hold no reservation with them. The provider you choose handles payment, confirmation, changes and refunds. How that works.
Staying in Waterloo
Live rooms and prices for Waterloo are in the search below.
Book a hotel in Waterloo
Live rooms and prices from our booking partner, booked and paid for here. Free cancellation is marked where it applies.
Common questions
How far is Waterloo from London?
79 km (49 mi) in a straight line, north-east of London; by road roughly 97 km (60 mi).
How long does it take to get from London to Waterloo by road?
About 1 h 17 min, estimated from distance and typical speeds. Timetables and traffic decide the real figure.
Is there a time difference between London and Waterloo?
No, both are on America/Toronto at the moment.
Where these facts come from
- GeoNames (CC BY 4.0): population, elevation, time zone, postal codes
- Wikidata (CC0): area, sister cities, visitor numbers, heritage listings, stations and ports
- OurAirports (public domain): airports, runways
- Natural Earth (public domain): map outlines
Data compiled 13 September 2026. Hotel figures are from our booking partner’s catalogue on that date. Journey times on this page are estimates from distance, not timetables; check the operator before you rely on one.