Sandy Springs to Montgomery by bus
Montgomery lies 249 km (155 mi) south-west of Sandy Springs, -1 h on the clock. What the numbers say about getting there.
A coach takes about 4 h 43 min including stops, over roughly 304 km (189 mi) of road.
Open Montgomery in Google Maps
| Sandy Springs | Montgomery | |
|---|---|---|
| Country | United States | United States |
| Population | 105,330 | 195,287 |
| Elevation | 333 m (1,093 ft) | 76 m (249 ft) |
| Time now | UTC-4 (America/New_York) | UTC-5 (America/Chicago) |
Clocks in Montgomery are 1 h behind Sandy Springs right now, so a 4 h 43 min journey lands only 3 h 43 min later by the destination clock.
Where to book buses from Sandy Springs to Montgomery
We take no bookings for these providers and hold no reservation with them. The provider you choose handles payment, confirmation, changes and refunds. How that works.
Staying in Montgomery
Live rooms and prices for Montgomery are in the search below.
Book a hotel in Montgomery
Live rooms and prices from our booking partner, booked and paid for here. Free cancellation is marked where it applies.
Common questions
How far is Montgomery from Sandy Springs?
249 km (155 mi) in a straight line, south-west of Sandy Springs; by road roughly 304 km (189 mi).
How long does it take to get from Sandy Springs to Montgomery by bus?
About 4 h 43 min, estimated from distance and typical speeds. Timetables and traffic decide the real figure.
Is there a time difference between Sandy Springs and Montgomery?
Montgomery is 1 h behind at the moment (America/Chicago against America/New_York).
Where these facts come from
- GeoNames (CC BY 4.0): population, elevation, time zone, postal codes
- Wikidata (CC0): area, sister cities, visitor numbers, heritage listings, stations and ports
- OurAirports (public domain): airports, runways
- Natural Earth (public domain): map outlines
Data compiled 13 September 2026. Hotel figures are from our booking partner’s catalogue on that date. Journey times on this page are estimates from distance, not timetables; check the operator before you rely on one.