Pingliang to Yinchuan by bus
Yinchuan lies 328 km (204 mi) north of Pingliang, in the same time zone. What the numbers say about getting there.
A coach takes about 6 h 8 min including stops, over roughly 400 km (248 mi) of road.
| Pingliang | Yinchuan | |
|---|---|---|
| Country | China | China |
| Population | 504,848 | 2.9 million |
| Elevation | 1,354 m (4,442 ft) | 1,117 m (3,665 ft) |
| Time now | UTC+8 (Asia/Shanghai) | UTC+8 (Asia/Shanghai) |
| Postal codes | 744000 | 750000 |
Where to book buses from Pingliang to Yinchuan
We take no bookings for these providers and hold no reservation with them. The provider you choose handles payment, confirmation, changes and refunds. How that works.
Staying in Yinchuan
Our booking partner lists 47 places to stay in Yinchuan. Of the 42 with a star rating, the largest group is 4-star (15), and 6 are five-star. Guests have left 169 reviews in total.
Book a hotel in Yinchuan
Live rooms and prices from our booking partner, booked and paid for here. Free cancellation is marked where it applies.
Common questions
How far is Yinchuan from Pingliang?
328 km (204 mi) in a straight line, north of Pingliang; by road roughly 400 km (248 mi).
How long does it take to get from Pingliang to Yinchuan by bus?
About 6 h 8 min, estimated from distance and typical speeds. Timetables and traffic decide the real figure.
Is there a time difference between Pingliang and Yinchuan?
No, both are on Asia/Shanghai at the moment.
Where can I stay in Yinchuan?
Our booking partner lists 47 places to stay in Yinchuan, bookable on this site.
Where these facts come from
- GeoNames (CC BY 4.0): population, elevation, time zone, postal codes
- Wikidata (CC0): area, sister cities, visitor numbers, heritage listings, stations and ports
- OurAirports (public domain): airports, runways
- Natural Earth (public domain): map outlines
Data compiled 14 September 2026. Hotel and hostel figures are from our booking partner’s catalogue on that date. Journey times on this page are estimates from distance, not timetables; check the operator before you rely on one.