Day trip from Jieyang to Ganzhou
Ganzhou lies 294 km (183 mi) north-west of Jieyang, in the same time zone. What the numbers say about getting there.
At 294 km (183 mi) apart, Ganzhou is a realistic day trip from Jieyang: about 4 h 47 min each way by road.
| Jieyang | Ganzhou | |
|---|---|---|
| Country | China | China |
| Population | 1.9 million | 2 million |
| Elevation | 7 m (23 ft) | 117 m (384 ft) |
| Time now | UTC+8 (Asia/Shanghai) | UTC+8 (Asia/Shanghai) |
| Postal codes | 522000 | 341000 |
Where to book tours and tickets in Ganzhou
We take no bookings for these providers and hold no reservation with them. The provider you choose handles payment, confirmation, changes and refunds. How that works.
Staying in Ganzhou
Our booking partner lists 31 places to stay in Ganzhou. Of the 25 with a star rating, the largest group is 3-star (9), and 4 are five-star. Guests have left 18 reviews in total.
Book a hotel in Ganzhou
Live rooms and prices from our booking partner, booked and paid for here. Free cancellation is marked where it applies.
Common questions
How far is Ganzhou from Jieyang?
294 km (183 mi) in a straight line, north-west of Jieyang; by road roughly 359 km (223 mi).
How long does it take to get from Jieyang to Ganzhou by road?
About 4 h 47 min, estimated from distance and typical speeds. Timetables and traffic decide the real figure.
Is there a time difference between Jieyang and Ganzhou?
No, both are on Asia/Shanghai at the moment.
Where can I stay in Ganzhou?
Our booking partner lists 31 places to stay in Ganzhou, bookable on this site.
Where these facts come from
- GeoNames (CC BY 4.0): population, elevation, time zone, postal codes
- Wikidata (CC0): area, sister cities, visitor numbers, heritage listings, stations and ports
- OurAirports (public domain): airports, runways
- Natural Earth (public domain): map outlines
Data compiled 14 September 2026. Hotel and hostel figures are from our booking partner’s catalogue on that date. Journey times on this page are estimates from distance, not timetables; check the operator before you rely on one.